Run Detail
completedgemma-3-4b-it30 answersRecorded for this video
Provider
openrouter
Challenge Version
v1.0
Turns
30
Duration
26.7s
Total Tokens
7,803
Input Tokens
4,038
Output Tokens
3,765
Reasoning Effort
default
Cached Input Tokens
2,928
Est. Cost
$0.0003
Started
11/4/2026, 9:40:07 PM
OR Provider
Parasail
Finish Reason
stop
Generation ID
gen-1793828430-wFb5gAgDzlXUXlsrNnXl
Turns (30)
Turn #1Raw score: 1
85 in105 out80 cached190 total2.8s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write is_leap(year: int) -> bool to return whether year is a leap year in the Gregorian calendar.
assistant
def is_leap(year: int) -> bool:
"""
Return whether `year` is a leap year in the Gregorian calendar.
"""
if year % 4 == 0:
if year % 100 == 0:
if year % 400 == 0:
return True
else:
return False
else:
return True
else:
return False
Turn #2Raw score: 1
85 in134 out219 total3.5s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write is_leap(year: int) -> bool to return whether year is a leap year in the Gregorian calendar.
assistant
def is_leap(year: int) -> bool:
"""
Determine if a year is a leap year in the Gregorian calendar.
A leap year is divisible by 4, but not divisible by 100 unless it is also divisible by 400.
"""
if year % 4 == 0:
if year % 100 == 0:
if year % 400 == 0:
return True
else:
return False
else:
return True
else:
return False
Turn #3Raw score: 1
85 in105 out80 cached190 total2.8s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write is_leap(year: int) -> bool to return whether year is a leap year in the Gregorian calendar.
assistant
def is_leap(year: int) -> bool:
"""
Determine whether a given year is a leap year in the Gregorian calendar.
"""
if year % 4 == 0:
if year % 100 == 0:
if year % 400 == 0:
return True
else:
return False
else:
return True
else:
return False
Turn #4Raw score: 1
123 in115 out48 cached238 total3.1s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write rle(s: str) -> str to perform run-length encoding on s. Replace each run of consecutive identical characters with that character followed by the run length. rle("aaabcc") returns "a3b1c2" and rle("") returns "".
assistant
def rle(s: str) -> str:
if not s:
return ""
result = ""
count = 1
for i in range(1, len(s)):
if s[i] == s[i - 1]:
count += 1
else:
result += s[i - 1] + str(count)
count = 1
result += s[-1] + str(count)
return result
Turn #5Raw score: 1
123 in115 out112 cached238 total2.7s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write rle(s: str) -> str to perform run-length encoding on s. Replace each run of consecutive identical characters with that character followed by the run length. rle("aaabcc") returns "a3b1c2" and rle("") returns "".
assistant
def rle(s: str) -> str:
if not s:
return ""
result = ""
count = 1
for i in range(1, len(s)):
if s[i] == s[i - 1]:
count += 1
else:
result += s[i - 1] + str(count)
count = 1
result += s[-1] + str(count)
return result
Turn #6Raw score: 1
123 in115 out112 cached238 total2.7s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write rle(s: str) -> str to perform run-length encoding on s. Replace each run of consecutive identical characters with that character followed by the run length. rle("aaabcc") returns "a3b1c2" and rle("") returns "".
assistant
def rle(s: str) -> str:
if not s:
return ""
result = ""
count = 1
for i in range(1, len(s)):
if s[i] == s[i - 1]:
count += 1
else:
result += s[i - 1] + str(count)
count = 1
result += s[-1] + str(count)
return result
Turn #7Raw score: 0
117 in105 out48 cached222 total2.5s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write chunks(items, n: int) -> list[list]. items is an iterable, which may be a generator. Return consecutive lists of n elements, where the last list may be shorter. Raise ValueError when n is less than 1.
assistant
def chunks(items, n: int) -> list[list]:
if n < 1:
raise ValueError("Chunk size must be at least 1")
it = iter(items)
while True:
chunk = []
try:
for _ in range(n):
chunk.append(next(it))
except StopIteration:
if chunk:
yield chunk
return
yield chunk
Turn #8Raw score: 0
117 in87 out112 cached204 total2.1s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write chunks(items, n: int) -> list[list]. items is an iterable, which may be a generator. Return consecutive lists of n elements, where the last list may be shorter. Raise ValueError when n is less than 1.
assistant
def chunks(items, n: int) -> list[list]:
if n < 1:
raise ValueError("Chunk size must be at least 1")
it = iter(items)
while True:
chunk = list(itertools.islice(it, n))
if not chunk:
return
yield chunk
import itertools
Turn #9Raw score: 0
117 in104 out112 cached221 total2.7s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write chunks(items, n: int) -> list[list]. items is an iterable, which may be a generator. Return consecutive lists of n elements, where the last list may be shorter. Raise ValueError when n is less than 1.
assistant
def chunks(items, n: int) -> list[list]:
if n < 1:
raise ValueError("Chunk size must be at least 1")
it = iter(items)
while True:
chunk = list(it)
if not chunk:
return []
if len(chunk) == n:
yield chunk
else:
yield chunk
it = iter(chunk)
Turn #10Raw score: 0
159 in79 out48 cached238 total2.1s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write round_half_up(value: str, digits: int) -> str. The string value represents a decimal number. Round it to digits decimal places, rounding exact ties away from zero based on the exact value written in value. Return a string with exactly digits decimal places, and omit the decimal point when digits is 0. round_half_up("2.675", 2) returns "2.68".
assistant
def round_half_up(value: str, digits: int) -> str:
value = float(value)
rounded_value = round(value, digits)
if digits == 0:
return str(int(rounded_value))
return "{:.{}f}".format(rounded_value, digits)
Turn #11Raw score: 0
159 in72 out144 cached231 total1.9s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write round_half_up(value: str, digits: int) -> str. The string value represents a decimal number. Round it to digits decimal places, rounding exact ties away from zero based on the exact value written in value. Return a string with exactly digits decimal places, and omit the decimal point when digits is 0. round_half_up("2.675", 2) returns "2.68".
assistant
def round_half_up(value: str, digits: int) -> str:
value = float(value)
if digits == 0:
return str(int(value))
factor = 10 ** digits
return str(round(value * factor) / factor)
Turn #12Raw score: 0
159 in79 out144 cached238 total2.1s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write round_half_up(value: str, digits: int) -> str. The string value represents a decimal number. Round it to digits decimal places, rounding exact ties away from zero based on the exact value written in value. Return a string with exactly digits decimal places, and omit the decimal point when digits is 0. round_half_up("2.675", 2) returns "2.68".
assistant
def round_half_up(value: str, digits: int) -> str:
value = float(value)
rounded_value = round(value, digits)
if digits == 0:
return str(int(rounded_value))
return "{:.{}f}".format(rounded_value, digits)
Turn #13Raw score: 0
151 in218 out48 cached369 total5.1s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write parse_kv(line: str) -> dict[str, str]. The string line contains key=value pairs separated by one or more spaces. A value may be enclosed in double quotes; if so, it may contain spaces and =, and the quotes are not included in the parsed value. A value may be empty, as in c=. If a key repeats, use the last value. Return {} for an empty line.
assistant
def parse_kv(line: str) -> dict[str, str]:
"""
The string `line` contains key=value pairs separated by one or more spaces.
A value may be enclosed in double quotes; if so, it may contain spaces and `=`,
and the quotes are not included in the parsed value. A value may be empty, as in `c=`.
If a key repeats, use the last value.
Return `{}` for an empty line.
"""
result = {}
if not line:
return result
for kv_pair in line.split():
if "=" in kv_pair:
key, value = kv_pair.split("=", 1)
if value.startswith('"') and value.endswith('"'):
value = value[1:-1]
result[key] = value
elif kv_pair:
result[kv_pair] = ""
return result
Turn #14Raw score: 0
151 in137 out144 cached288 total3.3s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write parse_kv(line: str) -> dict[str, str]. The string line contains key=value pairs separated by one or more spaces. A value may be enclosed in double quotes; if so, it may contain spaces and =, and the quotes are not included in the parsed value. A value may be empty, as in c=. If a key repeats, use the last value. Return {} for an empty line.
assistant
def parse_kv(line: str) -> dict[str, str]:
"""Parses a string containing key=value pairs into a dictionary.
Args:
line: The string to parse.
Returns:
A dictionary mapping keys to values.
"""
result = {}
if not line:
return result
for pair in line.split():
if "=" in pair:
key, value = pair.split("=", 1)
result[key] = value
elif pair:
result[pair] = ""
return result
Turn #15Raw score: 0
151 in195 out144 cached346 total4.7s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write parse_kv(line: str) -> dict[str, str]. The string line contains key=value pairs separated by one or more spaces. A value may be enclosed in double quotes; if so, it may contain spaces and =, and the quotes are not included in the parsed value. A value may be empty, as in c=. If a key repeats, use the last value. Return {} for an empty line.
assistant
def parse_kv(line: str) -> dict[str, str]:
"""
The string `line` contains key=value pairs separated by one or more spaces.
A value may be enclosed in double quotes; if so, it may contain spaces and `=`,
and the quotes are not included in the parsed value. A value may be empty, as in `c=`.
If a key repeats, use the last value.
Return `{}` for an empty line.
"""
result = {}
if not line:
return result
pairs = line.split()
for pair in pairs:
if "=" in pair:
key, value = pair.split("=", 1)
if value:
result[key] = value
elif pair:
result[pair] = ""
return result
Turn #16Raw score: 0
141 in107 out48 cached248 total2.6s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write merge_intervals(intervals: list[tuple[int, int]]) -> list[tuple[int, int]]. The input intervals may be in any order. Merge intervals that overlap or touch, so (1, 2) and (2, 3) become (1, 3). Return the merged intervals as tuples sorted by start, and leave the input list unchanged.
assistant
def merge_intervals(intervals: list[tuple[int, int]]) -> list[tuple[int, int]]:
intervals.sort()
merged = []
for interval in intervals:
if not merged or interval[0] > merged[-1][1]:
merged.append(interval)
else:
merged[-1] = (merged[-1][0], max(merged[-1][1], interval[1]))
return merged
Turn #17Raw score: 0
141 in107 out128 cached248 total2.6s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write merge_intervals(intervals: list[tuple[int, int]]) -> list[tuple[int, int]]. The input intervals may be in any order. Merge intervals that overlap or touch, so (1, 2) and (2, 3) become (1, 3). Return the merged intervals as tuples sorted by start, and leave the input list unchanged.
assistant
def merge_intervals(intervals: list[tuple[int, int]]) -> list[tuple[int, int]]:
intervals.sort()
merged = []
for interval in intervals:
if not merged or interval[0] > merged[-1][1]:
merged.append(interval)
else:
merged[-1] = (merged[-1][0], max(merged[-1][1], interval[1]))
return merged
Turn #18Raw score: 0
141 in107 out128 cached248 total2.6s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write merge_intervals(intervals: list[tuple[int, int]]) -> list[tuple[int, int]]. The input intervals may be in any order. Merge intervals that overlap or touch, so (1, 2) and (2, 3) become (1, 3). Return the merged intervals as tuples sorted by start, and leave the input list unchanged.
assistant
def merge_intervals(intervals: list[tuple[int, int]]) -> list[tuple[int, int]]:
intervals.sort()
merged = []
for interval in intervals:
if not merged or interval[0] > merged[-1][1]:
merged.append(interval)
else:
merged[-1] = (merged[-1][0], max(merged[-1][1], interval[1]))
return merged
Turn #19Raw score: 1
115 in138 out48 cached253 total7.3s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write add_months(d: datetime.date, months: int) -> datetime.date to add months calendar months to d. months may be negative. If the day does not exist in the target month, use the last day of that month.
assistant
import datetime
def add_months(d: datetime.date, months: int) -> datetime.date:
month = d.month - 1 + months
year = d.year + month // 12
month = month % 12 + 1
try:
return d.replace(year=year, month=month, day=d.day)
except ValueError:
import calendar
last_day = calendar.monthrange(year, month)[1]
return d.replace(year=year, month=month, day=last_day)
Turn #20Raw score: 1
115 in133 out112 cached248 total7.0s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write add_months(d: datetime.date, months: int) -> datetime.date to add months calendar months to d. months may be negative. If the day does not exist in the target month, use the last day of that month.
assistant
import datetime
def add_months(d: datetime.date, months: int) -> datetime.date:
month = d.month - 1 + months
year = d.year + month // 12
month = month % 12 + 1
try:
return d.replace(year=year, month=month)
except ValueError:
import calendar
last_day = calendar.monthrange(year, month)[1]
return d.replace(year=year, month=month, day=last_day)
Turn #21Raw score: 1
115 in138 out112 cached253 total6.9s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write add_months(d: datetime.date, months: int) -> datetime.date to add months calendar months to d. months may be negative. If the day does not exist in the target month, use the last day of that month.
assistant
import datetime
def add_months(d: datetime.date, months: int) -> datetime.date:
month = d.month - 1 + months
year = d.year + month // 12
month = month % 12 + 1
try:
return d.replace(year=year, month=month, day=d.day)
except ValueError:
import calendar
last_day = calendar.monthrange(year, month)[1]
return d.replace(year=year, month=month, day=last_day)
Turn #22Raw score: 1
138 in98 out48 cached236 total6.1s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write top_k_words(text: str, k: int) -> list[tuple[str, int]]. A word is a maximal sequence of ASCII letters and apostrophes. Words compare case-insensitively and are returned in lowercase. Return the k most frequent words as (word, count) tuples, sorted by highest count first, breaking ties alphabetically by word.
assistant
from collections import Counter
import re
def top_k_words(text: str, k: int) -> list[tuple[str, int]]:
words = re.findall(r"[a-zA-Z']+", text.lower())
word_counts = Counter(words)
return sorted(word_counts.items(), key=lambda item: (-item[1], item[0]))[:k]
Turn #23Raw score: 1
138 in98 out128 cached236 total2.3s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write top_k_words(text: str, k: int) -> list[tuple[str, int]]. A word is a maximal sequence of ASCII letters and apostrophes. Words compare case-insensitively and are returned in lowercase. Return the k most frequent words as (word, count) tuples, sorted by highest count first, breaking ties alphabetically by word.
assistant
from collections import Counter
import re
def top_k_words(text: str, k: int) -> list[tuple[str, int]]:
words = re.findall(r"[a-zA-Z']+", text.lower())
word_counts = Counter(words)
return sorted(word_counts.items(), key=lambda item: (-item[1], item[0]))[:k]
Turn #24Raw score: 1
138 in175 out128 cached313 total3.7s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write top_k_words(text: str, k: int) -> list[tuple[str, int]]. A word is a maximal sequence of ASCII letters and apostrophes. Words compare case-insensitively and are returned in lowercase. Return the k most frequent words as (word, count) tuples, sorted by highest count first, breaking ties alphabetically by word.
assistant
from collections import Counter
def top_k_words(text: str, k: int) -> list[tuple[str, int]]:
words = []
current_word = ""
for char in text:
if 'a' <= char <= 'z' or 'A' <= char <= 'Z' or char == "'":
current_word += char.lower()
else:
if current_word:
words.append(current_word)
current_word = ""
if current_word:
words.append(current_word)
word_counts = Counter(words)
return sorted(word_counts.items(), key=lambda item: (-item[1], item[0]))[:k]
Turn #25Raw score: 0
174 in141 out48 cached315 total3.0s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write flatten(obj: dict, sep: str = ".") -> dict. Flatten nested dicts and lists into a single level, joining keys with sep and using list indices as keys. Keep an empty dict or empty list as the value at its key. flatten({"a": {"b": 1}, "c": [{"d": 2}, 3], "e": {}}) returns {"a.b": 1, "c.0.d": 2, "c.1": 3, "e": {}}.
assistant
def flatten(obj: dict, sep: str = ".") -> dict:
result = {}
for k, v in obj.items():
if isinstance(v, dict):
result.update(flatten(v, sep=sep).items())
elif isinstance(v, list):
for i, elem in enumerate(v):
if isinstance(elem, dict):
result.update(flatten(elem, sep=sep).items())
else:
result[k + "." + str(i)] = elem
else:
result[k] = v
return result
Turn #26Raw score: 0
174 in141 out160 cached315 total3.0s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write flatten(obj: dict, sep: str = ".") -> dict. Flatten nested dicts and lists into a single level, joining keys with sep and using list indices as keys. Keep an empty dict or empty list as the value at its key. flatten({"a": {"b": 1}, "c": [{"d": 2}, 3], "e": {}}) returns {"a.b": 1, "c.0.d": 2, "c.1": 3, "e": {}}.
assistant
def flatten(obj: dict, sep: str = ".") -> dict:
result = {}
for key, value in obj.items():
if isinstance(value, dict):
result.update(flatten(value, sep=sep).items())
elif isinstance(value, list):
for i, item in enumerate(value):
if isinstance(item, dict):
result.update(flatten(item, sep=sep).items())
else:
result[key + "." + str(i)] = item
else:
result[key] = value
return result
Turn #27Raw score: 0
174 in162 out160 cached336 total3.5s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write flatten(obj: dict, sep: str = ".") -> dict. Flatten nested dicts and lists into a single level, joining keys with sep and using list indices as keys. Keep an empty dict or empty list as the value at its key. flatten({"a": {"b": 1}, "c": [{"d": 2}, 3], "e": {}}) returns {"a.b": 1, "c.0.d": 2, "c.1": 3, "e": {}}.
assistant
def flatten(obj: dict, sep: str = ".") -> dict:
result = {}
def flatten_helper(obj, prefix=""):
if isinstance(obj, dict):
for k, v in obj.items():
new_prefix = prefix + sep + k if prefix else k
flatten_helper(v, new_prefix)
elif isinstance(obj, list):
for i, v in enumerate(obj):
new_prefix = prefix + sep + str(i) if prefix else str(i)
flatten_helper(v, new_prefix)
else:
result[prefix] = obj
flatten_helper(obj)
return result
Turn #28Raw score: 1
143 in151 out48 cached294 total3.3s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write lru(maxsize: int), a decorator factory that caches a function's results by its positional arguments without using functools.lru_cache or functools.cache. It stores at most maxsize results. When the cache is full, evict the least recently used result. A cache hit counts as a use. The decorated function must preserve its original __name__.
assistant
def lru(maxsize: int):
def decorator(func):
cache = {}
usage = []
def wrapper(*args):
if args in cache:
usage.remove(args)
usage.append(args)
return cache[args]
else:
result = func(*args)
cache[args] = result
usage.append(args)
if len(cache) > maxsize:
oldest = usage.pop(0)
del cache[oldest]
return result
wrapper.__name__ = func.__name__
return wrapper
return decorator
Turn #29Raw score: 0
143 in153 out128 cached296 total3.3s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write lru(maxsize: int), a decorator factory that caches a function's results by its positional arguments without using functools.lru_cache or functools.cache. It stores at most maxsize results. When the cache is full, evict the least recently used result. A cache hit counts as a use. The decorated function must preserve its original __name__.
assistant
import collections
def lru(maxsize: int):
def decorator_factory(func):
cache = collections.OrderedDict(maxlen=maxsize)
def wrapper(*args, **kwargs):
key = (args, tuple(sorted(kwargs.items())))
if key in cache:
cache.move_to_end(key)
return cache[key]
else:
result = func(*args, **kwargs)
cache[key] = result
cache.move_to_end(key)
return result
wrapper.__name__ = func.__name__
return wrapper
return decorator_factory
Turn #30Raw score: 1
143 in151 out128 cached294 total3.2s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write lru(maxsize: int), a decorator factory that caches a function's results by its positional arguments without using functools.lru_cache or functools.cache. It stores at most maxsize results. When the cache is full, evict the least recently used result. A cache hit counts as a use. The decorated function must preserve its original __name__.
assistant
def lru(maxsize: int):
def decorator(func):
cache = {}
history = []
def wrapper(*args):
if args in cache:
history.remove(args)
history.append(args)
return cache[args]
else:
result = func(*args)
cache[args] = result
history.append(args)
if len(cache) > maxsize:
oldest = history.pop(0)
del cache[oldest]
return result
wrapper.__name__ = func.__name__
return wrapper
return decorator