Run Detail
completedgpt-oss-20b3 answersRecorded for these videos
Provider
openrouter
Challenge Version
v1.0
Turns
3
Duration
175.7s
Total Tokens
3,088
Input Tokens
627
Output Tokens
2,461
Reasoning Tokens
1,911
Reasoning Effort
default
Est. Cost
$0.0004
Started
11/5/2026, 2:35:34 AM
OR Provider
DeepInfra
Finish Reason
stop
Generation ID
gen-1793846293-o1dACIgJKM2Exedr0pR7
Turns (3)
Turn #11Raw score: 1
208 in807 out649 reasoning1,015 total11.8s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write parse_pair<T: FromStr>(s: &str, sep: char) -> Option<(T, T)>, importing FromStr yourself. Split s at the first occurrence of sep and parse both sides as T. Return None if sep does not occur or if either side fails to parse. sep may be any Unicode character. parse_pair::<u32>("400x600", 'x') returns Some((400, 600)).
assistant
use std::str::FromStr;
fn parse_pair<T: FromStr>(s: &str, sep: char) -> Option<(T, T)> {
let mut parts = s.splitn(2, sep);
let left = parts.next()?;
let right = parts.next()?;
let left_val = left.parse::<T>().ok()?;
let right_val = right.parse::<T>().ok()?;
Some((left_val, right_val))
}
Turn #16Raw score: 0
182 in717 out510 reasoning899 total10.2s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Define Fib, with a constructor Fib::new(), and implement Iterator<Item = u64> for it. It yields the Fibonacci numbers 0, 1, 1, 2, 3, 5, and so on. It yields every Fibonacci number that fits in a u64, then None from then on. Tests run with overflow checks on.
assistant
pub struct Fib {
a: u64,
b: u64,
finished: bool,
}
impl Fib {
pub fn new() -> Self {
Self {
a: 0,
b: 1,
finished: false,
}
}
}
impl Iterator for Fib {
type Item = u64;
fn next(&mut self) -> Option<Self::Item> {
if self.finished {
return None;
}
let current = self.a;
match self.a.checked_add(self.b) {
Some(sum) => {
self.a = self.b;
self.b = sum;
Some(current)
}
None => {
self.finished = true;
Some(current)
}
}
}
}
Turn #30Raw score: 1
237 in937 out752 reasoning1,174 total19.7s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Define TreeNode with exactly these fields: value: i32, parent: RefCell<Weak<TreeNode>>, and children: RefCell<Vec<Rc<TreeNode>>>, importing those types from the standard library. Write TreeNode::new(value: i32) -> Rc<TreeNode>. Write TreeNode::add_child(parent: &Rc<TreeNode>, child: Rc<TreeNode>), which also sets the child's parent. Write sum(&self) -> i32, the total of this node and all its descendants, and depth(&self) -> usize, the number of ancestors, which is 0 for a root.
assistant
use std::cell::RefCell;
use std::rc::{Rc, Weak};
pub struct TreeNode {
pub value: i32,
pub parent: RefCell<Weak<TreeNode>>,
pub children: RefCell<Vec<Rc<TreeNode>>>,
}
impl TreeNode {
pub fn new(value: i32) -> Rc<TreeNode> {
Rc::new(TreeNode {
value,
parent: RefCell::new(Weak::new()),
children: RefCell::new(Vec::new()),
})
}
pub fn add_child(parent: &Rc<TreeNode>, child: Rc<TreeNode>) {
*child.parent.borrow_mut() = Rc::downgrade(parent);
parent.children.borrow_mut().push(child);
}
pub fn sum(&self) -> i32 {
let mut total = self.value;
for child in self.children.borrow().iter() {
total += child.sum();
}
total
}
pub fn depth(&self) -> usize {
match self.parent.borrow().upgrade() {
Some(parent) => 1 + parent.depth(),
None => 0,
}
}
}