Run Detail
completednemotron-3.5-super-vl30 answersRecorded for these videos
Provider
openrouter
Challenge Version
v1.0
Turns
30
Duration
363.1s
Total Tokens
102,993
Input Tokens
4,707
Output Tokens
98,286
Reasoning Tokens
92,510
Reasoning Effort
default
Est. Cost
$0.0398
Started
11/6/2026, 12:06:20 PM
OR Provider
Crusoe
Finish Reason
stop
Generation ID
gen-1793967094-l60yJcZydWOszHqo63Q9
Turns (30)
Turn #1Raw score: 1
107 in1,765 out1,484 reasoning1,872 total30.6s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write is_palindrome(s: &str) -> bool. Consider only ASCII letters and digits, ignoring ASCII case and every other character. A string with none of those characters is a palindrome.
assistant
pub fn is_palindrome(s: &str) -> bool {
let bytes = s.as_bytes();
let mut left = 0;
let mut right = bytes.len();
while left < right {
while left < right && !is_ascii_alphanumeric(bytes[left]) {
left += 1;
}
while left < right && !is_ascii_alphanumeric(bytes[right - 1]) {
right -= 1;
}
if left >= right {
break;
}
if to_ascii_lowercase(bytes[left]) != to_ascii_lowercase(bytes[right - 1]) {
return false;
}
left += 1;
right -= 1;
}
true
}
const fn is_ascii_alphanumeric(b: u8) -> bool {
(b >= b'0' && b <= b'9')
|| (b >= b'A' && b <= b'Z')
|| (b >= b'a' && b <= b'z')
}
const fn to_ascii_lowercase(b: u8) -> u8 {
if b >= b'A' && b <= b'Z' {
b + (b'a' - b'A')
} else {
b
}
}
Turn #2Raw score: 1
107 in2,024 out1,729 reasoning2,131 total23.5s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write is_palindrome(s: &str) -> bool. Consider only ASCII letters and digits, ignoring ASCII case and every other character. A string with none of those characters is a palindrome.
assistant
pub fn is_palindrome(s: &str) -> bool {
let bytes = s.as_bytes();
let mut left = 0;
let mut right = bytes.len();
while left < right {
while left < right {
let b = bytes[left];
if matches!(b, b'0'..=b'9' | b'A'..=b'Z' | b'a'..=b'z') {
break;
}
left += 1;
}
while left < right {
let b = bytes[right - 1];
if matches!(b, b'0'..=b'9' | b'A'..=b'Z' | b'a'..=b'z') {
break;
}
right -= 1;
}
if left >= right {
break;
}
let l = bytes[left];
let r = bytes[right - 1];
let l = if l >= b'A' && l <= b'Z' { l + 32 } else { l };
let r = if r >= b'A' && r <= b'Z' { r + 32 } else { r };
if l != r {
return false;
}
left += 1;
right -= 1;
}
true
}
Turn #3Raw score: 1
107 in1,185 out966 reasoning1,292 total24.4s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write is_palindrome(s: &str) -> bool. Consider only ASCII letters and digits, ignoring ASCII case and every other character. A string with none of those characters is a palindrome.
assistant
fn is_palindrome(s: &str) -> bool {
let bytes = s.as_bytes();
let mut left = 0;
let mut right = bytes.len();
while left < right {
while left < right && !is_ascii_alphanumeric(bytes[left]) {
left += 1;
}
while left < right && !is_ascii_alphanumeric(bytes[right - 1]) {
right -= 1;
}
if left >= right {
break;
}
if bytes[left].to_ascii_lowercase() != bytes[right - 1].to_ascii_lowercase() {
return false;
}
left += 1;
right -= 1;
}
true
}
fn is_ascii_alphanumeric(b: u8) -> bool {
matches!(b, b'0'..=b'9' | b'A'..=b'Z' | b'a'..=b'z')
}
Turn #4Raw score: 1
118 in738 out655 reasoning856 total7.8s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write word_count(text: &str) -> HashMap<String, usize>, importing HashMap yourself. Words are separated by any whitespace and compared in lowercase, and the map's keys are lowercase. Punctuation is part of a word.
assistant
use std::collections::HashMap;
pub fn word_count(text: &str) -> HashMap<String, usize> {
let mut counts = HashMap::new();
for word in text.split_whitespace() {
let key = word.to_lowercase();
*counts.entry(key).or_insert(0) += 1;
}
counts
}
Turn #5Raw score: 1
118 in594 out511 reasoning712 total5.8s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write word_count(text: &str) -> HashMap<String, usize>, importing HashMap yourself. Words are separated by any whitespace and compared in lowercase, and the map's keys are lowercase. Punctuation is part of a word.
assistant
use std::collections::HashMap;
pub fn word_count(text: &str) -> HashMap<String, usize> {
let mut counts = HashMap::new();
for word in text.split_whitespace() {
let key = word.to_lowercase();
*counts.entry(key).or_insert(0) += 1;
}
counts
}
Turn #6Raw score: 1
118 in713 out630 reasoning831 total10.0s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write word_count(text: &str) -> HashMap<String, usize>, importing HashMap yourself. Words are separated by any whitespace and compared in lowercase, and the map's keys are lowercase. Punctuation is part of a word.
assistant
use std::collections::HashMap;
pub fn word_count(text: &str) -> HashMap<String, usize> {
let mut counts = HashMap::new();
for word in text.split_whitespace() {
let key = word.to_lowercase();
*counts.entry(key).or_insert(0) += 1;
}
counts
}
Turn #7Raw score: 1
112 in374 out323 reasoning486 total3.8s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write longest, which takes two string slices and returns the longer one by str::len without allocating. On a tie, it returns the first. Its result must be usable as long as both inputs are alive.
assistant
fn longest<'a>(x: &'a str, y: &'a str) -> &'a str {
if x.len() >= y.len() {
x
} else {
y
}
}
Turn #8Raw score: 1
112 in699 out648 reasoning811 total11.4s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write longest, which takes two string slices and returns the longer one by str::len without allocating. On a tie, it returns the first. Its result must be usable as long as both inputs are alive.
assistant
fn longest<'a>(x: &'a str, y: &'a str) -> &'a str {
if x.len() >= y.len() {
x
} else {
y
}
}
Turn #9Raw score: 1
112 in792 out741 reasoning904 total6.8s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write longest, which takes two string slices and returns the longer one by str::len without allocating. On a tie, it returns the first. Its result must be usable as long as both inputs are alive.
assistant
fn longest<'a>(x: &'a str, y: &'a str) -> &'a str {
if x.len() >= y.len() {
x
} else {
y
}
}
Turn #10Raw score: 1
181 in1,180 out1,093 reasoning1,361 total14.5s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write parse_pair<T: FromStr>(s: &str, sep: char) -> Option<(T, T)>, importing FromStr yourself. Split s at the first occurrence of sep and parse both sides as T. Return None if sep does not occur or if either side fails to parse. sep may be any Unicode character. parse_pair::<u32>("400x600", 'x') returns Some((400, 600)).
assistant
use std::str::FromStr;
fn parse_pair<T: FromStr>(s: &str, sep: char) -> Option<(T, T)> {
let (left, right) = s.split_once(sep)?;
let left = T::from_str(left).ok()?;
let right = T::from_str(right).ok()?;
Some((left, right))
}
Turn #11Raw score: 1
181 in526 out441 reasoning707 total6.5s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write parse_pair<T: FromStr>(s: &str, sep: char) -> Option<(T, T)>, importing FromStr yourself. Split s at the first occurrence of sep and parse both sides as T. Return None if sep does not occur or if either side fails to parse. sep may be any Unicode character. parse_pair::<u32>("400x600", 'x') returns Some((400, 600)).
assistant
use std::str::FromStr;
fn parse_pair<T: FromStr>(s: &str, sep: char) -> Option<(T, T)> {
let (left, right) = s.split_once(sep)?;
let left = left.parse::<T>().ok()?;
let right = right.parse::<T>().ok()?;
Some((left, right))
}
Turn #12Raw score: 1
181 in631 out544 reasoning812 total6.1s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write parse_pair<T: FromStr>(s: &str, sep: char) -> Option<(T, T)>, importing FromStr yourself. Split s at the first occurrence of sep and parse both sides as T. Return None if sep does not occur or if either side fails to parse. sep may be any Unicode character. parse_pair::<u32>("400x600", 'x') returns Some((400, 600)).
assistant
use std::str::FromStr;
fn parse_pair<T: FromStr>(s: &str, sep: char) -> Option<(T, T)> {
let (left, right) = s.split_once(sep)?;
let left = T::from_str(left).ok()?;
let right = T::from_str(right).ok()?;
Some((left, right))
}
Turn #13Raw score: 1
135 in3,127 out3,061 reasoning3,262 total45.1s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write compose(f, g), generic over the argument and result types. f and g are closures implementing Fn. It returns a closure implementing Fn that maps x to g(f(x)), and the returned closure must be usable after the function that called compose has returned.
assistant
fn compose<F, G, A, B, C>(f: F, g: G) -> impl Fn(A) -> C
where
F: Fn(A) -> B,
G: Fn(B) -> C,
{
move |x| g(f(x))
}
Turn #14Raw score: 1
135 in2,128 out2,062 reasoning2,263 total29.0s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write compose(f, g), generic over the argument and result types. f and g are closures implementing Fn. It returns a closure implementing Fn that maps x to g(f(x)), and the returned closure must be usable after the function that called compose has returned.
assistant
fn compose<F, G, A, B, C>(f: F, g: G) -> impl Fn(A) -> C
where
F: Fn(A) -> B,
G: Fn(B) -> C,
{
move |x| g(f(x))
}
Turn #15Raw score: 1
135 in1,743 out1,677 reasoning1,878 total22.1s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write compose(f, g), generic over the argument and result types. f and g are closures implementing Fn. It returns a closure implementing Fn that maps x to g(f(x)), and the returned closure must be usable after the function that called compose has returned.
assistant
fn compose<F, G, A, B, C>(f: F, g: G) -> impl Fn(A) -> C
where
F: Fn(A) -> B,
G: Fn(B) -> C,
{
move |x| g(f(x))
}
Turn #16Raw score: 1
151 in13,581 out13,362 reasoning13,732 total180.3s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Define Fib, with a constructor Fib::new(), and implement Iterator<Item = u64> for it. It yields the Fibonacci numbers 0, 1, 1, 2, 3, 5, and so on. It yields every Fibonacci number that fits in a u64, then None from then on. Tests run with overflow checks on.
assistant
pub struct Fib {
state: FibState,
}
enum FibState {
Active(u64, u64),
Last(u64),
Done,
}
impl Fib {
pub fn new() -> Self {
Self {
state: FibState::Active(0, 1),
}
}
}
impl Iterator for Fib {
type Item = u64;
fn next(&mut self) -> Option<Self::Item> {
let state = std::mem::replace(&mut self.state, FibState::Done);
match state {
FibState::Active(a, b) => {
let ret = a;
self.state = match b.checked_add(a) {
Some(sum) => FibState::Active(b, sum),
None => FibState::Last(b),
};
Some(ret)
}
FibState::Last(a) => {
self.state = FibState::Done;
Some(a)
}
FibState::Done => None,
}
}
}
Turn #17Raw score: 1
151 in7,790 out7,596 reasoning7,941 total100.0s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Define Fib, with a constructor Fib::new(), and implement Iterator<Item = u64> for it. It yields the Fibonacci numbers 0, 1, 1, 2, 3, 5, and so on. It yields every Fibonacci number that fits in a u64, then None from then on. Tests run with overflow checks on.
assistant
pub struct Fib {
curr: Option<u64>,
next: Option<u64>,
}
impl Fib {
pub fn new() -> Self {
Self {
curr: Some(0),
next: Some(1),
}
}
}
impl Iterator for Fib {
type Item = u64;
fn next(&mut self) -> Option<Self::Item> {
let current = self.curr.take()?;
let next_val = match self.next.take() {
Some(n) => n,
None => return Some(current),
};
match current.checked_add(next_val) {
Some(sum) => {
self.curr = Some(next_val);
self.next = Some(sum);
Some(current)
}
None => {
self.curr = Some(next_val);
self.next = None;
Some(current)
}
}
}
}
Turn #18Raw score: 1
151 in9,749 out9,507 reasoning9,900 total139.2s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Define Fib, with a constructor Fib::new(), and implement Iterator<Item = u64> for it. It yields the Fibonacci numbers 0, 1, 1, 2, 3, 5, and so on. It yields every Fibonacci number that fits in a u64, then None from then on. Tests run with overflow checks on.
assistant
pub struct Fib {
state: State,
}
enum State {
Active { curr: u64, next: u64 },
Last { val: u64 },
Done,
}
impl Fib {
pub fn new() -> Self {
Fib {
state: State::Active { curr: 0, next: 1 },
}
}
}
impl Iterator for Fib {
type Item = u64;
fn next(&mut self) -> Option<Self::Item> {
match std::mem::replace(&mut self.state, State::Done) {
State::Active { curr, next } => {
let result = curr;
match curr.checked_add(next) {
Some(sum) => {
self.state = State::Active { curr: next, next: sum };
Some(result)
}
None => {
self.state = State::Last { val: next };
Some(result)
}
}
}
State::Last { val } => {
self.state = State::Done;
Some(val)
}
State::Done => None,
}
}
}
Turn #19Raw score: 1
254 in3,558 out3,153 reasoning3,812 total43.5s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Define enum TempError deriving Debug, with the variants Empty, BadUnit(char), and BadNumber(std::num::ParseFloatError), and write parse_temp(s: &str) -> Result<f64, TempError>. The input is a number followed by one unit character, C or F, and the result is in Celsius, so "212F" returns 100.0. An empty string gives Empty. If the last character is neither C nor F, it gives BadUnit with that character, which may be non-ASCII. A number that does not parse gives BadNumber. Implement Display and std::error::Error for TempError, with source() returning the parse error for BadNumber, and implement From<std::num::ParseFloatError> for it.
assistant
use std::fmt;
#[derive(Debug)]
enum TempError {
Empty,
BadUnit(char),
BadNumber(std::num::ParseFloatError),
}
impl fmt::Display for TempError {
fn fmt(&self, f: &mut fmt::Formatter<'_>) -> fmt::Result {
match self {
TempError::Empty => write!(f, "empty input"),
TempError::BadUnit(c) => write!(f, "invalid unit: {}", c),
TempError::BadNumber(e) => write!(f, "invalid number: {}", e),
}
}
}
impl std::error::Error for TempError {
fn source(&self) -> Option<&(dyn std::error::Error + 'static)> {
match self {
TempError::BadNumber(e) => Some(e),
_ => None,
}
}
}
impl From<std::num::ParseFloatError> for TempError {
fn from(e: std::num::ParseFloatError) -> Self {
TempError::BadNumber(e)
}
}
fn parse_temp(s: &str) -> Result<f64, TempError> {
if s.is_empty() {
return Err(TempError::Empty);
}
let unit = s.chars().last().expect("string is not empty");
let unit_len = unit.len_utf8();
let num_str = &s[..s.len() - unit_len];
match unit {
'C' | 'F' => {
let value: f64 = num_str.parse().map_err(TempError::BadNumber)?;
if unit == 'F' {
Ok((value - 32.0) * 5.0 / 9.0)
} else {
Ok(value)
}
}
other => Err(TempError::BadUnit(other)),
}
}
Turn #20Raw score: 1
254 in3,326 out2,923 reasoning3,580 total39.6s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Define enum TempError deriving Debug, with the variants Empty, BadUnit(char), and BadNumber(std::num::ParseFloatError), and write parse_temp(s: &str) -> Result<f64, TempError>. The input is a number followed by one unit character, C or F, and the result is in Celsius, so "212F" returns 100.0. An empty string gives Empty. If the last character is neither C nor F, it gives BadUnit with that character, which may be non-ASCII. A number that does not parse gives BadNumber. Implement Display and std::error::Error for TempError, with source() returning the parse error for BadNumber, and implement From<std::num::ParseFloatError> for it.
assistant
use std::fmt::{self, Display, Formatter};
use std::num::ParseFloatError;
#[derive(Debug)]
pub enum TempError {
Empty,
BadUnit(char),
BadNumber(ParseFloatError),
}
impl Display for TempError {
fn fmt(&self, f: &mut Formatter<'_>) -> fmt::Result {
match self {
TempError::Empty => write!(f, "empty input"),
TempError::BadUnit(c) => write!(f, "bad unit: '{c}'"),
TempError::BadNumber(e) => write!(f, "bad number: {e}"),
}
}
}
impl std::error::Error for TempError {
fn source(&self) -> Option<&(dyn std::error::Error + 'static)> {
match self {
TempError::BadNumber(e) => Some(e),
_ => None,
}
}
}
impl From<ParseFloatError> for TempError {
fn from(e: ParseFloatError) -> Self {
TempError::BadNumber(e)
}
}
pub fn parse_temp(s: &str) -> Result<f64, TempError> {
if s.is_empty() {
return Err(TempError::Empty);
}
let Some(unit) = s.chars().next_back() else {
return Err(TempError::Empty);
};
if unit != 'C' && unit != 'F' {
return Err(TempError::BadUnit(unit));
}
let num_str = &s[..s.len() - unit.len_utf8()];
let value: f64 = num_str.parse()?;
if unit == 'F' {
Ok((value - 32.0) * 5.0 / 9.0)
} else {
Ok(value)
}
}
Turn #21Raw score: 1
254 in8,808 out8,409 reasoning9,062 total120.0s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Define enum TempError deriving Debug, with the variants Empty, BadUnit(char), and BadNumber(std::num::ParseFloatError), and write parse_temp(s: &str) -> Result<f64, TempError>. The input is a number followed by one unit character, C or F, and the result is in Celsius, so "212F" returns 100.0. An empty string gives Empty. If the last character is neither C nor F, it gives BadUnit with that character, which may be non-ASCII. A number that does not parse gives BadNumber. Implement Display and std::error::Error for TempError, with source() returning the parse error for BadNumber, and implement From<std::num::ParseFloatError> for it.
assistant
#[derive(Debug)]
pub enum TempError {
Empty,
BadUnit(char),
BadNumber(std::num::ParseFloatError),
}
impl std::fmt::Display for TempError {
fn fmt(&self, f: &mut std::fmt::Formatter<'_>) -> std::fmt::Result {
match self {
TempError::Empty => write!(f, "empty temperature input"),
TempError::BadUnit(unit) => write!(f, "invalid unit: {unit}"),
TempError::BadNumber(error) => write!(f, "invalid number: {error}"),
}
}
}
impl std::error::Error for TempError {
fn source(&self) -> Option<&(dyn std::error::Error + 'static)> {
match self {
TempError::BadNumber(error) => Some(error),
_ => None,
}
}
}
impl From<std::num::ParseFloatError> for TempError {
fn from(error: std::num::ParseFloatError) -> Self {
TempError::BadNumber(error)
}
}
pub fn parse_temp(s: &str) -> Result<f64, TempError> {
if s.is_empty() {
return Err(TempError::Empty);
}
let unit = s.chars().next_back().unwrap();
let number_text = &s[..s.len() - unit.len_utf8()];
match unit {
'C' => number_text.parse::<f64>().map_err(TempError::BadNumber),
'F' => {
let value = number_text.parse::<f64>().map_err(TempError::BadNumber)?;
Ok((value - 32.0) * 5.0 / 9.0)
}
_ => Err(TempError::BadUnit(unit)),
}
}
Turn #22Raw score: 1
155 in3,043 out2,820 reasoning3,198 total47.9s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write parallel_sum(data: &[u64], workers: usize) -> u64, which sums data by splitting it across workers threads from std::thread. data is a borrowed slice, and workers may be larger than data.len(). It returns 0 for an empty slice and panics when workers is 0, including when the slice is empty.
assistant
use std::thread;
pub fn parallel_sum(data: &[u64], workers: usize) -> u64 {
assert!(workers > 0, "workers must be non-zero");
if data.is_empty() {
return 0;
}
let len = data.len();
let n = workers.min(len);
let base = len / n;
let rem = len % n;
thread::scope(|s| {
let mut handles = Vec::with_capacity(n);
let mut start = 0;
for i in 0..n {
let extra = if i < rem { 1 } else { 0 };
let end = start + base + extra;
let chunk = &data[start..end];
start = end;
handles.push(s.spawn(move || chunk.iter().sum::<u64>()));
}
let mut total = 0;
for handle in handles {
total += handle.join().unwrap();
}
total
})
}
Turn #23Raw score: 0
155 in3,290 out3,065 reasoning3,445 total47.2s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write parallel_sum(data: &[u64], workers: usize) -> u64, which sums data by splitting it across workers threads from std::thread. data is a borrowed slice, and workers may be larger than data.len(). It returns 0 for an empty slice and panics when workers is 0, including when the slice is empty.
assistant
pub fn parallel_sum(data: &[u64], workers: usize) -> u64 {
if workers == 0 {
panic!("workers must be non-zero");
}
if data.is_empty() {
return 0;
}
let len = data.len();
let num_workers = workers.min(len);
let base_chunk = len / num_workers;
let remainder = len % num_workers;
std::thread::scope(|scope| {
let mut handles = Vec::with_capacity(num_workers);
let mut start = 0;
for i in 0..num_workers {
let end = start + base_chunk + if i < remainder { 1 } else { 0 };
let chunk = &data[start..end];
start = end;
handles.push(scope.spawn(move || {
chunk.iter().sum()
}));
}
let mut total = 0;
for handle in handles {
total += handle.join();
}
total
})
}
Turn #24Raw score: 1
155 in2,314 out2,135 reasoning2,469 total27.4s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Write parallel_sum(data: &[u64], workers: usize) -> u64, which sums data by splitting it across workers threads from std::thread. data is a borrowed slice, and workers may be larger than data.len(). It returns 0 for an empty slice and panics when workers is 0, including when the slice is empty.
assistant
use std::thread;
pub fn parallel_sum(data: &[u64], workers: usize) -> u64 {
if workers == 0 {
panic!("parallel_sum: workers must be non-zero");
}
if data.is_empty() {
return 0;
}
let workers = workers.min(data.len());
let chunk_size = (data.len() + workers - 1) / workers;
thread::scope(|s| {
let handles: Vec<_> = data
.chunks(chunk_size)
.map(|chunk| {
s.spawn(move || chunk.iter().copied().sum::<u64>())
})
.collect();
handles
.into_iter()
.map(|handle| handle.join().unwrap())
.sum()
})
}
Turn #25Raw score: 0
141 in8,407 out8,093 reasoning8,548 total92.6s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Define an extension trait PairsExt that adds a method .pairs() to every iterator whose items implement Clone. It returns a lazy iterator of consecutive overlapping pairs, so (1..4).pairs() yields (1, 2) then (2, 3). A source with fewer than two items yields nothing, and an infinite source must work.
assistant
pub trait PairsExt: Iterator {
fn pairs(self) -> Pairs<Self>
where
Self: Sized,
Self::Item: Clone;
}
impl<I: Iterator> PairsExt for I {
fn pairs(self) -> Pairs<Self>
where
Self: Sized,
Self::Item: Clone,
{
Pairs {
iter: self,
prev: None,
done: false,
}
}
}
pub struct Pairs<I: Iterator> {
iter: I,
prev: Option<I::Item>,
done: bool,
}
impl<I: Iterator> Iterator for Pairs<I>
where
I::Item: Clone,
{
type Item = (I::Item, I::Item);
fn next(&mut self) -> Option<Self::Item> {
if self.done {
return None;
}
let prev = self.prev.take();
match prev {
None => match self.iter.next() {
Some(item) => {
self.prev = Some(item);
None
}
None => {
self.done = true;
None
}
},
Some(prev_item) => match self.iter.next() {
Some(item) => {
let pair = (prev_item.clone(), item);
self.prev = Some(item);
Some(pair)
}
None => {
self.done = true;
None
}
},
}
}
}
Turn #26Raw score: 1
141 in4,086 out3,805 reasoning4,227 total61.9s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Define an extension trait PairsExt that adds a method .pairs() to every iterator whose items implement Clone. It returns a lazy iterator of consecutive overlapping pairs, so (1..4).pairs() yields (1, 2) then (2, 3). A source with fewer than two items yields nothing, and an infinite source must work.
assistant
pub trait PairsExt: Iterator {
fn pairs(self) -> Pairs<Self>
where
Self: Sized,
Self::Item: Clone;
}
impl<I> PairsExt for I
where
I: Iterator,
I::Item: Clone,
{
fn pairs(self) -> Pairs<Self> {
Pairs::new(self)
}
}
pub struct Pairs<I: Iterator> {
iter: I,
front: Option<I::Item>,
}
impl<I: Iterator> Pairs<I> {
fn new(iter: I) -> Self {
Self { iter, front: None }
}
}
impl<I> Iterator for Pairs<I>
where
I: Iterator,
I::Item: Clone,
{
type Item = (I::Item, I::Item);
fn next(&mut self) -> Option<Self::Item> {
let first = match self.front.take() {
Some(item) => item,
None => match self.iter.next() {
Some(item) => item,
None => return None,
},
};
let second = match self.iter.next() {
Some(item) => item,
None => return None,
};
self.front = Some(second.clone());
Some((first, second))
}
}
Turn #27Raw score: 0
141 in3,641 out3,422 reasoning3,782 total44.2s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Define an extension trait PairsExt that adds a method .pairs() to every iterator whose items implement Clone. It returns a lazy iterator of consecutive overlapping pairs, so (1..4).pairs() yields (1, 2) then (2, 3). A source with fewer than two items yields nothing, and an infinite source must work.
assistant
pub struct Pairs<I: Iterator> {
iter: I,
prev: Option<I::Item>,
}
impl<I> Iterator for Pairs<I>
where
I: Iterator,
I::Item: Clone,
{
type Item = (I::Item, I::Item);
fn next(&mut self) -> Option<Self::Item> {
loop {
let curr = match self.iter.next() {
Some(item) => item,
None => return None,
};
match self.prev.take() {
None => self.prev = Some(curr),
Some(prev) => {
self.prev = Some(curr);
return Some((prev, curr.clone()));
}
}
}
}
}
pub trait PairsExt: Iterator {
fn pairs(self) -> Pairs<Self>
where
Self: Sized,
Self::Item: Clone,
{
Pairs { iter: self, prev: None }
}
}
impl<I: Iterator> PairsExt for I {}
Turn #28Raw score: 0
215 in2,742 out2,464 reasoning2,957 total30.9s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Define TreeNode with exactly these fields: value: i32, parent: RefCell<Weak<TreeNode>>, and children: RefCell<Vec<Rc<TreeNode>>>, importing those types from the standard library. Write TreeNode::new(value: i32) -> Rc<TreeNode>. Write TreeNode::add_child(parent: &Rc<TreeNode>, child: Rc<TreeNode>), which also sets the child's parent. Write sum(&self) -> i32, the total of this node and all its descendants, and depth(&self) -> usize, the number of ancestors, which is 0 for a root.
assistant
#![edition = "2024"]
use std::cell::RefCell;
use std::rc::{Rc, Weak};
pub struct TreeNode {
value: i32,
parent: RefCell<Weak<TreeNode>>,
children: RefCell<Vec<Rc<TreeNode>>>,
}
impl TreeNode {
pub fn new(value: i32) -> Rc<TreeNode> {
Rc::new(TreeNode {
value,
parent: RefCell::new(Weak::new()),
children: RefCell::new(Vec::new()),
})
}
pub fn add_child(parent: &Rc<TreeNode>, child: Rc<TreeNode>) {
*child.parent.borrow_mut() = Rc::downgrade(parent);
parent.children.borrow_mut().push(child);
}
pub fn sum(&self) -> i32 {
let mut total = self.value;
for child in self.children.borrow().iter() {
total += child.sum();
}
total
}
pub fn depth(&self) -> usize {
match self.parent.borrow().upgrade() {
Some(p) => 1 + p.depth(),
None => 0,
}
}
}
Turn #29Raw score: 1
215 in3,412 out3,148 reasoning3,627 total57.4s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Define TreeNode with exactly these fields: value: i32, parent: RefCell<Weak<TreeNode>>, and children: RefCell<Vec<Rc<TreeNode>>>, importing those types from the standard library. Write TreeNode::new(value: i32) -> Rc<TreeNode>. Write TreeNode::add_child(parent: &Rc<TreeNode>, child: Rc<TreeNode>), which also sets the child's parent. Write sum(&self) -> i32, the total of this node and all its descendants, and depth(&self) -> usize, the number of ancestors, which is 0 for a root.
assistant
use std::cell::RefCell;
use std::rc::{Rc, Weak};
struct TreeNode {
value: i32,
parent: RefCell<Weak<TreeNode>>,
children: RefCell<Vec<Rc<TreeNode>>>,
}
impl TreeNode {
fn new(value: i32) -> Rc<TreeNode> {
Rc::new(TreeNode {
value,
parent: RefCell::new(Weak::new()),
children: RefCell::new(Vec::new()),
})
}
fn add_child(parent: &Rc<TreeNode>, child: Rc<TreeNode>) {
*child.parent.borrow_mut() = Rc::downgrade(parent);
parent.children.borrow_mut().push(child);
}
fn sum(&self) -> i32 {
let mut total = self.value;
for child in self.children.borrow().iter() {
total += child.sum();
}
total
}
fn depth(&self) -> usize {
match self.parent.borrow().upgrade() {
Some(ancestor) => 1 + ancestor.depth(),
None => 0,
}
}
}
Turn #30Raw score: 1
215 in2,320 out2,043 reasoning2,535 total48.6s
user
Write Rust for the 2024 edition on stable, using only the standard library. Answer with one ```rust code block that defines what the question describes. Do not include fn main, tests, examples, explanations, or print statements.
Define TreeNode with exactly these fields: value: i32, parent: RefCell<Weak<TreeNode>>, and children: RefCell<Vec<Rc<TreeNode>>>, importing those types from the standard library. Write TreeNode::new(value: i32) -> Rc<TreeNode>. Write TreeNode::add_child(parent: &Rc<TreeNode>, child: Rc<TreeNode>), which also sets the child's parent. Write sum(&self) -> i32, the total of this node and all its descendants, and depth(&self) -> usize, the number of ancestors, which is 0 for a root.
assistant
use std::cell::RefCell;
use std::rc::{Rc, Weak};
pub struct TreeNode {
pub value: i32,
pub parent: RefCell<Weak<TreeNode>>,
pub children: RefCell<Vec<Rc<TreeNode>>>,
}
impl TreeNode {
pub fn new(value: i32) -> Rc<Self> {
Rc::new(TreeNode {
value,
parent: RefCell::new(Weak::new()),
children: RefCell::new(Vec::new()),
})
}
pub fn add_child(parent: &Rc<TreeNode>, child: Rc<TreeNode>) {
*child.parent.borrow_mut() = Rc::downgrade(parent);
parent.children.borrow_mut().push(child);
}
pub fn sum(&self) -> i32 {
let mut total = self.value;
for child in self.children.borrow().iter() {
total += child.sum();
}
total
}
pub fn depth(&self) -> usize {
let parent = self.parent.borrow();
match parent.upgrade() {
Some(ancestor) => 1 + ancestor.depth(),
None => 0,
}
}
}