Run Detail
completednemotron-3-ultra-550b-a55b:free30 answersRecorded for these videos
Provider
openrouter
Challenge Version
v1.0
Turns
30
Duration
651.0s
Total Tokens
89,677
Input Tokens
4,176
Output Tokens
85,501
Reasoning Tokens
80,786
Reasoning Effort
default
Est. Cost
$0.0000
Started
11/6/2026, 1:13:29 PM
OR Provider
Nvidia
Finish Reason
stop
Generation ID
gen-1793970824-H76YIxoBEFn5XaEx31Qg
Turns (30)
Turn #1Raw score: 1
91 in178 out130 reasoning269 total3.3s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write is_leap(year: int) -> bool to return whether year is a leap year in the Gregorian calendar.
assistant
def is_leap(year: int) -> bool:
return year % 4 == 0 and (year % 100 != 0 or year % 400 == 0)
Turn #2Raw score: 1
91 in195 out147 reasoning286 total3.7s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write is_leap(year: int) -> bool to return whether year is a leap year in the Gregorian calendar.
assistant
def is_leap(year: int) -> bool:
return year % 4 == 0 and (year % 100 != 0 or year % 400 == 0)
Turn #3Raw score: 1
91 in347 out299 reasoning438 total5.5s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write is_leap(year: int) -> bool to return whether year is a leap year in the Gregorian calendar.
assistant
def is_leap(year: int) -> bool:
return year % 400 == 0 or (year % 4 == 0 and year % 100 != 0)
Turn #4Raw score: 1
128 in370 out271 reasoning498 total6.0s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write rle(s: str) -> str to perform run-length encoding on s. Replace each run of consecutive identical characters with that character followed by the run length. rle("aaabcc") returns "a3b1c2" and rle("") returns "".
assistant
def rle(s: str) -> str:
if not s:
return ""
result = []
count = 1
prev = s[0]
for char in s[1:]:
if char == prev:
count += 1
else:
result.append(prev + str(count))
prev = char
count = 1
result.append(prev + str(count))
return "".join(result)
Turn #5Raw score: 1
128 in400 out296 reasoning528 total9.2s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write rle(s: str) -> str to perform run-length encoding on s. Replace each run of consecutive identical characters with that character followed by the run length. rle("aaabcc") returns "a3b1c2" and rle("") returns "".
assistant
def rle(s: str) -> str:
if not s:
return ""
result = []
current_char = s[0]
count = 1
for char in s[1:]:
if char == current_char:
count += 1
else:
result.append(current_char + str(count))
current_char = char
count = 1
result.append(current_char + str(count))
return "".join(result)
Turn #6Raw score: 1
128 in367 out263 reasoning495 total24.8s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write rle(s: str) -> str to perform run-length encoding on s. Replace each run of consecutive identical characters with that character followed by the run length. rle("aaabcc") returns "a3b1c2" and rle("") returns "".
assistant
def rle(s: str) -> str:
if not s:
return ""
result = []
current_char = s[0]
count = 1
for char in s[1:]:
if char == current_char:
count += 1
else:
result.append(current_char + str(count))
current_char = char
count = 1
result.append(current_char + str(count))
return "".join(result)
Turn #7Raw score: 1
126 in240 out149 reasoning366 total5.7s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write chunks(items, n: int) -> list[list]. items is an iterable, which may be a generator. Return consecutive lists of n elements, where the last list may be shorter. Raise ValueError when n is less than 1.
assistant
def chunks(items, n: int) -> list[list]:
if n < 1:
raise ValueError("n must be at least 1")
result = []
chunk = []
for item in items:
chunk.append(item)
if len(chunk) == n:
result.append(chunk)
chunk = []
if chunk:
result.append(chunk)
return result
Turn #8Raw score: 1
126 in232 out141 reasoning358 total9.7s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write chunks(items, n: int) -> list[list]. items is an iterable, which may be a generator. Return consecutive lists of n elements, where the last list may be shorter. Raise ValueError when n is less than 1.
assistant
def chunks(items, n: int) -> list[list]:
if n < 1:
raise ValueError("n must be at least 1")
result = []
chunk = []
for item in items:
chunk.append(item)
if len(chunk) == n:
result.append(chunk)
chunk = []
if chunk:
result.append(chunk)
return result
Turn #9Raw score: 1
126 in387 out297 reasoning513 total11.0s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write chunks(items, n: int) -> list[list]. items is an iterable, which may be a generator. Return consecutive lists of n elements, where the last list may be shorter. Raise ValueError when n is less than 1.
assistant
def chunks(items, n: int) -> list[list]:
if n < 1:
raise ValueError("n must be >= 1")
result = []
chunk = []
for item in items:
chunk.append(item)
if len(chunk) == n:
result.append(chunk)
chunk = []
if chunk:
result.append(chunk)
return result
Turn #10Raw score: 1
165 in16,658 out16,241 reasoning16,823 total493.2s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write round_half_up(value: str, digits: int) -> str. The string value represents a decimal number. Round it to digits decimal places, rounding exact ties away from zero based on the exact value written in value. Return a string with exactly digits decimal places, and omit the decimal point when digits is 0. round_half_up("2.675", 2) returns "2.68".
assistant
def round_half_up(value: str, digits: int) -> str:
value = value.strip()
sign = ''
if value.startswith('-'):
sign = '-'
value = value[1:]
elif value.startswith('+'):
value = value[1:]
if '.' in value:
integer_part, fractional_part = value.split('.')
else:
integer_part, fractional_part = value, ''
integer_part = integer_part.lstrip('0')
if integer_part == '':
integer_part = '0'
round_up = False
if digits == 0:
if fractional_part and fractional_part[0] >= '5':
round_up = True
else:
if len(fractional_part) > digits and fractional_part[digits] >= '5':
round_up = True
if round_up:
prefix = integer_part
if digits > 0:
frac_prefix = fractional_part[:digits].ljust(digits, '0')
prefix += frac_prefix
new_prefix = str(int(prefix) + 1)
if digits == 0:
integer_part = new_prefix
fractional_part = ''
else:
if len(new_prefix) <= digits:
integer_part = '0'
fractional_part = new_prefix.zfill(digits)
else:
integer_part = new_prefix[:-digits]
fractional_part = new_prefix[-digits:]
else:
if digits > 0:
fractional_part = fractional_part[:digits].ljust(digits, '0')
else:
fractional_part = ''
is_zero = (integer_part == '0' and (digits == 0 or all(c == '0' for c in fractional_part)))
if is_zero:
sign = ''
if digits == 0:
return sign + integer_part
else:
return sign + integer_part + '.' + fractional_part
Turn #11Raw score: 1
165 in23,730 out23,170 reasoning23,895 total635.3s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write round_half_up(value: str, digits: int) -> str. The string value represents a decimal number. Round it to digits decimal places, rounding exact ties away from zero based on the exact value written in value. Return a string with exactly digits decimal places, and omit the decimal point when digits is 0. round_half_up("2.675", 2) returns "2.68".
assistant
def round_half_up(value: str, digits: int) -> str:
def increment_string(s: str) -> str:
lst = list(s)
i = len(lst) - 1
carry = 1
while i >= 0 and carry:
d = ord(lst[i]) - 48 + carry
carry = d // 10
lst[i] = chr(48 + d % 10)
i -= 1
if carry:
lst.insert(0, '1')
return ''.join(lst)
sign = 1
if value.startswith('-'):
sign = -1
value = value[1:]
elif value.startswith('+'):
value = value[1:]
if '.' in value:
integer_part, fractional_part = value.split('.')
else:
integer_part, fractional_part = value, ''
integer_part = integer_part.lstrip('0') or '0'
if digits == 0:
rounding_digit = fractional_part[0] if fractional_part else '0'
if rounding_digit >= '5':
integer_part = increment_string(integer_part)
result = integer_part
if sign == -1 and result != '0':
result = '-' + result
return result
else:
if len(fractional_part) <= digits:
rounded_fractional = fractional_part.ljust(digits, '0')
result_int = integer_part
else:
rounding_digit = fractional_part[digits]
keep_fractional = fractional_part[:digits]
if rounding_digit >= '5':
combined = integer_part + keep_fractional
incremented = increment_string(combined)
if len(incremented) > len(combined):
new_int = incremented[:-digits]
new_frac = incremented[-digits:]
else:
new_int = incremented[:-digits]
new_frac = incremented[-digits:]
result_int = new_int
rounded_fractional = new_frac
else:
result_int = integer_part
rounded_fractional = keep_fractional
rounded_fractional = rounded_fractional.ljust(digits, '0')
result = result_int + '.' + rounded_fractional
if sign == -1:
if result_int == '0' and all(c == '0' for c in rounded_fractional):
return result
else:
return '-' + result
else:
return result
Turn #12Raw score: 1
165 in7,087 out6,956 reasoning7,252 total166.0s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write round_half_up(value: str, digits: int) -> str. The string value represents a decimal number. Round it to digits decimal places, rounding exact ties away from zero based on the exact value written in value. Return a string with exactly digits decimal places, and omit the decimal point when digits is 0. round_half_up("2.675", 2) returns "2.68".
assistant
from decimal import Decimal, ROUND_HALF_UP, localcontext
def round_half_up(value: str, digits: int) -> str:
with localcontext() as ctx:
ctx.prec = max(len(value) + digits + 10, 100)
d = Decimal(value)
if digits > 0:
quant = Decimal('1e-{}'.format(digits))
else:
quant = Decimal('1')
rounded = d.quantize(quant, rounding=ROUND_HALF_UP)
return format(rounded, 'f')
Turn #13Raw score: 1
157 in2,911 out2,597 reasoning3,068 total97.5s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write parse_kv(line: str) -> dict[str, str]. The string line contains key=value pairs separated by one or more spaces. A value may be enclosed in double quotes; if so, it may contain spaces and =, and the quotes are not included in the parsed value. A value may be empty, as in c=. If a key repeats, use the last value. Return {} for an empty line.
assistant
def parse_kv(line: str) -> dict[str, str]:
result: dict[str, str] = {}
i = 0
n = len(line)
while i < n:
# Skip any whitespace
while i < n and line[i].isspace():
i += 1
if i >= n:
break
# Parse key (up to '=' or whitespace)
key_start = i
while i < n and line[i] != '=' and not line[i].isspace():
i += 1
if i >= n or line[i] != '=':
# Malformed pair; stop parsing
break
key = line[key_start:i]
i += 1 # skip '='
# Parse value
if i < n and line[i] == '"':
# Quoted value
i += 1
val_start = i
while i < n and line[i] != '"':
i += 1
value = line[val_start:i]
if i < n and line[i] == '"':
i += 1 # skip closing quote
else:
# Unquoted value (until whitespace or end)
val_start = i
while i < n and not line[i].isspace():
i += 1
value = line[val_start:i]
result[key] = value
return result
Turn #14Raw score: 1
157 in3,277 out3,029 reasoning3,434 total146.6s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write parse_kv(line: str) -> dict[str, str]. The string line contains key=value pairs separated by one or more spaces. A value may be enclosed in double quotes; if so, it may contain spaces and =, and the quotes are not included in the parsed value. A value may be empty, as in c=. If a key repeats, use the last value. Return {} for an empty line.
assistant
def parse_kv(line: str) -> dict[str, str]:
result = {}
i = 0
n = len(line)
while i < n:
while i < n and line[i].isspace():
i += 1
if i >= n:
break
key_start = i
while i < n and line[i] != '=' and not line[i].isspace():
i += 1
key = line[key_start:i]
if i >= n or line[i] != '=':
break
i += 1
if i < n and line[i] == '"':
i += 1
val_start = i
while i < n and line[i] != '"':
i += 1
value = line[val_start:i]
if i < n and line[i] == '"':
i += 1
else:
val_start = i
while i < n and not line[i].isspace():
i += 1
value = line[val_start:i]
result[key] = value
return result
Turn #15Raw score: 1
157 in4,520 out4,263 reasoning4,677 total120.0s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write parse_kv(line: str) -> dict[str, str]. The string line contains key=value pairs separated by one or more spaces. A value may be enclosed in double quotes; if so, it may contain spaces and =, and the quotes are not included in the parsed value. A value may be empty, as in c=. If a key repeats, use the last value. Return {} for an empty line.
assistant
def parse_kv(line: str) -> dict[str, str]:
result = {}
i = 0
n = len(line)
while i < n:
while i < n and line[i].isspace():
i += 1
if i >= n:
break
key_start = i
while i < n and line[i] != '=' and not line[i].isspace():
i += 1
key = line[key_start:i]
if i < n and line[i] == '=':
i += 1
else:
result[key] = ''
continue
if i < n and line[i] == '"':
i += 1
val_start = i
while i < n and line[i] != '"':
i += 1
value = line[val_start:i]
if i < n and line[i] == '"':
i += 1
else:
val_start = i
while i < n and not line[i].isspace():
i += 1
value = line[val_start:i]
result[key] = value
return result
Turn #16Raw score: 1
143 in396 out262 reasoning539 total12.0s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write merge_intervals(intervals: list[tuple[int, int]]) -> list[tuple[int, int]]. The input intervals may be in any order. Merge intervals that overlap or touch, so (1, 2) and (2, 3) become (1, 3). Return the merged intervals as tuples sorted by start, and leave the input list unchanged.
assistant
def merge_intervals(intervals: list[tuple[int, int]]) -> list[tuple[int, int]]:
if not intervals:
return []
sorted_intervals = sorted(intervals, key=lambda x: (x[0], x[1]))
merged = [sorted_intervals[0]]
for start, end in sorted_intervals[1:]:
last_start, last_end = merged[-1]
if start <= last_end:
merged[-1] = (last_start, max(last_end, end))
else:
merged.append((start, end))
return merged
Turn #17Raw score: 1
143 in536 out394 reasoning679 total8.1s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write merge_intervals(intervals: list[tuple[int, int]]) -> list[tuple[int, int]]. The input intervals may be in any order. Merge intervals that overlap or touch, so (1, 2) and (2, 3) become (1, 3). Return the merged intervals as tuples sorted by start, and leave the input list unchanged.
assistant
def merge_intervals(intervals: list[tuple[int, int]]) -> list[tuple[int, int]]:
if not intervals:
return []
sorted_intervals = sorted(intervals, key=lambda x: x[0])
merged = []
current_start, current_end = sorted_intervals[0]
for start, end in sorted_intervals[1:]:
if start <= current_end:
current_end = max(current_end, end)
else:
merged.append((current_start, current_end))
current_start, current_end = start, end
merged.append((current_start, current_end))
return merged
Turn #18Raw score: 1
143 in554 out412 reasoning697 total14.6s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write merge_intervals(intervals: list[tuple[int, int]]) -> list[tuple[int, int]]. The input intervals may be in any order. Merge intervals that overlap or touch, so (1, 2) and (2, 3) become (1, 3). Return the merged intervals as tuples sorted by start, and leave the input list unchanged.
assistant
def merge_intervals(intervals: list[tuple[int, int]]) -> list[tuple[int, int]]:
if not intervals:
return []
sorted_intervals = sorted(intervals, key=lambda x: x[0])
merged = []
current_start, current_end = sorted_intervals[0]
for start, end in sorted_intervals[1:]:
if start <= current_end:
current_end = max(current_end, end)
else:
merged.append((current_start, current_end))
current_start, current_end = start, end
merged.append((current_start, current_end))
return merged
Turn #19Raw score: 1
118 in454 out330 reasoning572 total9.5s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write add_months(d: datetime.date, months: int) -> datetime.date to add months calendar months to d. months may be negative. If the day does not exist in the target month, use the last day of that month.
assistant
import datetime
import calendar
def add_months(d: datetime.date, months: int) -> datetime.date:
year = d.year
month = d.month + months
# Normalize year and month
year += (month - 1) // 12
month = (month - 1) % 12 + 1
# Determine last day of target month
last_day = calendar.monthrange(year, month)[1]
day = min(d.day, last_day)
return datetime.date(year, month, day)
Turn #20Raw score: 1
118 in840 out715 reasoning958 total25.8s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write add_months(d: datetime.date, months: int) -> datetime.date to add months calendar months to d. months may be negative. If the day does not exist in the target month, use the last day of that month.
assistant
import datetime
import calendar
def add_months(d: datetime.date, months: int) -> datetime.date:
total_months = d.year * 12 + d.month - 1 + months
new_year = total_months // 12
new_month = total_months % 12 + 1
try:
return datetime.date(new_year, new_month, d.day)
except ValueError:
last_day = calendar.monthrange(new_year, new_month)[1]
return datetime.date(new_year, new_month, last_day)
Turn #21Raw score: 1
118 in335 out228 reasoning453 total6.5s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write add_months(d: datetime.date, months: int) -> datetime.date to add months calendar months to d. months may be negative. If the day does not exist in the target month, use the last day of that month.
assistant
import datetime
import calendar
def add_months(d: datetime.date, months: int) -> datetime.date:
year = d.year
month = d.month + months
year += (month - 1) // 12
month = (month - 1) % 12 + 1
last_day = calendar.monthrange(year, month)[1]
day = min(d.day, last_day)
return datetime.date(year, month, day)
Turn #22Raw score: 1
139 in1,314 out1,204 reasoning1,453 total38.1s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write top_k_words(text: str, k: int) -> list[tuple[str, int]]. A word is a maximal sequence of ASCII letters and apostrophes. Words compare case-insensitively and are returned in lowercase. Return the k most frequent words as (word, count) tuples, sorted by highest count first, breaking ties alphabetically by word.
assistant
import re
from collections import Counter
def top_k_words(text: str, k: int) -> list[tuple[str, int]]:
if k <= 0:
return []
words = re.findall(r"[A-Za-z']+", text)
words_lower = [w.lower() for w in words]
counts = Counter(words_lower)
sorted_items = sorted(counts.items(), key=lambda item: (-item[1], item[0]))
return sorted_items[:k]
Turn #23Raw score: 1
139 in1,283 out1,175 reasoning1,422 total75.1s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write top_k_words(text: str, k: int) -> list[tuple[str, int]]. A word is a maximal sequence of ASCII letters and apostrophes. Words compare case-insensitively and are returned in lowercase. Return the k most frequent words as (word, count) tuples, sorted by highest count first, breaking ties alphabetically by word.
assistant
import re
from collections import Counter
def top_k_words(text: str, k: int) -> list[tuple[str, int]]:
if k <= 0:
return []
words = re.findall(r"[A-Za-z']+", text)
words = [w.lower() for w in words]
counts = Counter(words)
sorted_items = sorted(counts.items(), key=lambda item: (-item[1], item[0]))
return sorted_items[:k]
Turn #24Raw score: 1
139 in1,441 out1,331 reasoning1,580 total67.8s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write top_k_words(text: str, k: int) -> list[tuple[str, int]]. A word is a maximal sequence of ASCII letters and apostrophes. Words compare case-insensitively and are returned in lowercase. Return the k most frequent words as (word, count) tuples, sorted by highest count first, breaking ties alphabetically by word.
assistant
import re
from collections import Counter
def top_k_words(text: str, k: int) -> list[tuple[str, int]]:
if k <= 0:
return []
words = re.findall(r"[A-Za-z']+", text)
words_lower = [w.lower() for w in words]
counts = Counter(words_lower)
sorted_items = sorted(counts.items(), key=lambda item: (-item[1], item[0]))
return sorted_items[:k]
Turn #25Raw score: 1
180 in2,921 out2,769 reasoning3,101 total70.4s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write flatten(obj: dict, sep: str = ".") -> dict. Flatten nested dicts and lists into a single level, joining keys with sep and using list indices as keys. Keep an empty dict or empty list as the value at its key. flatten({"a": {"b": 1}, "c": [{"d": 2}, 3], "e": {}}) returns {"a.b": 1, "c.0.d": 2, "c.1": 3, "e": {}}.
assistant
def flatten(obj: dict, sep: str = ".") -> dict:
result = {}
def _flatten(val, prefix):
if isinstance(val, dict):
if not val:
result[prefix] = {}
else:
for k, v in val.items():
_flatten(v, f"{prefix}{sep}{k}")
elif isinstance(val, list):
if not val:
result[prefix] = []
else:
for i, v in enumerate(val):
_flatten(v, f"{prefix}{sep}{i}")
else:
result[prefix] = val
for key, value in obj.items():
_flatten(value, key)
return result
Turn #26Raw score: 1
180 in4,711 out4,554 reasoning4,891 total184.2s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write flatten(obj: dict, sep: str = ".") -> dict. Flatten nested dicts and lists into a single level, joining keys with sep and using list indices as keys. Keep an empty dict or empty list as the value at its key. flatten({"a": {"b": 1}, "c": [{"d": 2}, 3], "e": {}}) returns {"a.b": 1, "c.0.d": 2, "c.1": 3, "e": {}}.
assistant
def flatten(obj: dict, sep: str = ".") -> dict:
result = {}
def _flatten(prefix: str, value):
if isinstance(value, dict):
if not value:
result[prefix] = value
else:
for k, v in value.items():
_flatten(f"{prefix}{sep}{k}", v)
elif isinstance(value, list):
if not value:
result[prefix] = value
else:
for i, v in enumerate(value):
_flatten(f"{prefix}{sep}{i}", v)
else:
result[prefix] = value
for k, v in obj.items():
_flatten(str(k), v)
return result
Turn #27Raw score: 1
180 in5,493 out5,330 reasoning5,673 total135.2s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write flatten(obj: dict, sep: str = ".") -> dict. Flatten nested dicts and lists into a single level, joining keys with sep and using list indices as keys. Keep an empty dict or empty list as the value at its key. flatten({"a": {"b": 1}, "c": [{"d": 2}, 3], "e": {}}) returns {"a.b": 1, "c.0.d": 2, "c.1": 3, "e": {}}.
assistant
def flatten(obj: dict, sep: str = ".") -> dict:
result = {}
def helper(prefix: str, value):
if isinstance(value, dict):
if not value:
result[prefix] = {}
else:
for k, v in value.items():
new_prefix = prefix + sep + str(k)
helper(new_prefix, v)
elif isinstance(value, list):
if not value:
result[prefix] = []
else:
for i, v in enumerate(value):
new_prefix = prefix + sep + str(i)
helper(new_prefix, v)
else:
result[prefix] = value
for k, v in obj.items():
helper(str(k), v)
return result
Turn #28Raw score: 1
145 in1,334 out1,161 reasoning1,479 total32.5s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write lru(maxsize: int), a decorator factory that caches a function's results by its positional arguments without using functools.lru_cache or functools.cache. It stores at most maxsize results. When the cache is full, evict the least recently used result. A cache hit counts as a use. The decorated function must preserve its original __name__.
assistant
from collections import OrderedDict
from functools import wraps
from typing import Any, Callable
def lru(maxsize: int):
def decorator(func: Callable[..., Any]):
cache: OrderedDict[tuple, Any] = OrderedDict()
@wraps(func)
def wrapper(*args: Any, **kwargs: Any) -> Any:
if maxsize <= 0:
return func(*args, **kwargs)
key = args
if key in cache:
value = cache.pop(key)
cache[key] = value
return value
value = func(*args, **kwargs)
if len(cache) >= maxsize:
cache.popitem(last=False)
cache[key] = value
return value
return wrapper
return decorator
Turn #29Raw score: 1
145 in1,184 out1,009 reasoning1,329 total33.0s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write lru(maxsize: int), a decorator factory that caches a function's results by its positional arguments without using functools.lru_cache or functools.cache. It stores at most maxsize results. When the cache is full, evict the least recently used result. A cache hit counts as a use. The decorated function must preserve its original __name__.
assistant
from collections import OrderedDict
from functools import wraps
from typing import Callable, Any
def lru(maxsize: int) -> Callable[[Callable[..., Any]], Callable[..., Any]]:
def decorator(func: Callable[..., Any]) -> Callable[..., Any]:
cache: OrderedDict[tuple, Any] = OrderedDict()
@wraps(func)
def wrapper(*args: Any) -> Any:
if args in cache:
result = cache[args]
cache.move_to_end(args)
return result
result = func(*args)
if maxsize > 0:
cache[args] = result
if len(cache) > maxsize:
cache.popitem(last=False)
return result
return wrapper
return decorator
Turn #30Raw score: 1
145 in1,806 out1,663 reasoning1,951 total39.9s
user
Write Python 3.13 code. Answer with one ```python code block that defines the function described below. Use only the standard library. Do not include explanations, examples, tests, input() calls, or print() calls.
Write lru(maxsize: int), a decorator factory that caches a function's results by its positional arguments without using functools.lru_cache or functools.cache. It stores at most maxsize results. When the cache is full, evict the least recently used result. A cache hit counts as a use. The decorated function must preserve its original __name__.
assistant
from collections import OrderedDict
from functools import wraps
def lru(maxsize: int):
def decorator(func):
if maxsize <= 0:
@wraps(func)
def wrapper(*args):
return func(*args)
return wrapper
cache = OrderedDict()
@wraps(func)
def wrapper(*args):
if args in cache:
cache.move_to_end(args)
return cache[args]
result = func(*args)
cache[args] = result
if len(cache) > maxsize:
cache.popitem(last=False)
return result
return wrapper
return decorator